![One - gram mole of nitrogen occupies 2 × 10^4 cc at a pressure of 10^6 dynes/cm^2 . The average energy of a nitrogen molecule (in erg) will be: (Avogadro's number = 6 × 10^25 ) One - gram mole of nitrogen occupies 2 × 10^4 cc at a pressure of 10^6 dynes/cm^2 . The average energy of a nitrogen molecule (in erg) will be: (Avogadro's number = 6 × 10^25 )](https://dwes9vv9u0550.cloudfront.net/images/4331944/26fe57cc-2075-4bd6-9313-2d68b6738f22.jpg)
One - gram mole of nitrogen occupies 2 × 10^4 cc at a pressure of 10^6 dynes/cm^2 . The average energy of a nitrogen molecule (in erg) will be: (Avogadro's number = 6 × 10^25 )
The value of Gravitional cons†an t in MKS system is 6.67×10^ 11 N m^2/kg^2. What will be its value in CGS system
![SOLVED: An object of mass 100 g is at rest. A net force of 2000 dynes is applied for 10 sec. What is the final velocity? How far will the object have SOLVED: An object of mass 100 g is at rest. A net force of 2000 dynes is applied for 10 sec. What is the final velocity? How far will the object have](https://cdn.numerade.com/ask_previews/295ae964-eee8-44ea-8636-a8c1109aebdb_large.jpg)
SOLVED: An object of mass 100 g is at rest. A net force of 2000 dynes is applied for 10 sec. What is the final velocity? How far will the object have
![Using Dimensional Analysis to Find the Quantity of a Substance Practice | Chemistry Practice Problems | Study.com Using Dimensional Analysis to Find the Quantity of a Substance Practice | Chemistry Practice Problems | Study.com](https://study.com/cimages/multimages/16/conversion_chart8444478195716729341.png)